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Question
A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is
${{W\left( {d - x} \right)} \over x}$
${{W\left( {d - x} \right)} \over d}$
${{Wx} \over d}$
${{Wd} \over x}$

Solution

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