When 22.4 liters of H2(g) is mixed with 11.2 litres of Cl2(g), each at S.T.P. the moles of HCl(g) formed is equal to

Question

When 22.4 liters of H_{2_(g)} is mixed with 11.2 litres of Cl_{2_(g)}, each at S.T.P. the moles of HCl_(g) formed is equal to

1 mol of HCl_(g)

2 mol of HCl_(g)

0.5 mol of HCl_(g)

1.5 mol of HCl_(g)

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