Steam at 100oC is passed into 20 g of water at 10oC. When water acquires a temperature of 80oC, the mass of water present will be [Take specific heat of water = 1 cal g$-$1 oC$-$1 and latent heat of steam = 540 cal g$-$1]

Question

Steam at 100^oC is passed into 20 g of water at 10^oC. When water acquires a temperature of 80^oC, the mass of water present will be
[Take specific heat of water = 1 cal g^$-$1 ^oC^$-$1 and latent heat of steam = 540 cal g^$-$1]