A thin semicircular conducting ring (PQR) of radius r is falling with its plane vertical in a horizontal magnetic field B, as shown in the figure. The potential difference developed across the ring when its speed is $v$, is

Question

A thin semicircular conducting ring (PQR) of radius r is falling with its plane vertical in a horizontal magnetic field B, as shown in the figure.

The potential difference developed across the ring when its speed is $v$, is

zero

${{Bv\pi {r^2}} \over 2}$ and P is at higher potential

$\pi rBV$ and R is at higher potential

2rBV and R is at higher potential

Solution

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