The molar specific heats of an ideal gas at constant pressure and volume are denoted by Cp and Cv, respectively. If $\gamma $ = ${{{C_p}} \over {{C_v}}}$ and R is the universal gas constant, then Cv is equal to

Question

The molar specific heats of an ideal gas at constant pressure and volume are denoted by C_p and C_v, respectively. If $\gamma $ = ${{{C_p}} \over {{C_v}}}$ and R is the universal gas constant, then C_v is equal to

${{\left( {\gamma - 1} \right)} \over R}$

$\gamma R$

${{1 + \gamma } \over {1 - \gamma }}$

${R \over {\left( {\gamma - 1} \right)}}$

Solution

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