For photoelectric emission from certain metal the cutoff frequency is $\upsilon $. If radiation of frequency 2$\upsilon $ impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass)

Question

$\sqrt {{{2h\upsilon } \over m}} $

$2\sqrt {{{h\upsilon } \over m}} $

$\sqrt {{{h\upsilon } \over {\left( {2m} \right)}}} $

$\sqrt {{{h\upsilon } \over m}} $

Solution

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