Molar conductivities $\left( {\Lambda _m^o} \right)$ at infinite dilution of NaCl, Hcl and CH3COONa are 126.4, 425.9 and 91.0 S cm2 mol$-$1 respectively. $\left( {\Lambda _m^o} \right)$ for CH3COOH will be
425.5 S cm2 mol$-$1
180.5 S cm2 mol$-$1
290.8 S cm2 mol$-$1
390.5 S cm2 mol$-$1
Solution
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