A magnetic needle suspended parallel to a magnetic field requires $\sqrt 3 J$ of work to turn it through 60o. The torque needed to maintain the needle in this position will be

Question

A magnetic needle suspended parallel to a magnetic field requires $\sqrt 3 J$ of work to turn it through 60^o. The torque needed to maintain the needle in this position will be

$2\sqrt 3 J$

$3$ $J$

$\sqrt 3 \,J$

${3 \over 2}\,J$

Solution

Please login to view the detailed solution steps...

Go to DASH