Limiting molar conductivity of NH4OH $\left[ {} \right.$i.e. $\Lambda _{m\left( {N{H_4}OH} \right)}^0$$\left. {} \right]$ is equal to

Question

Limiting molar conductivity of NH₄OH
$\left[ {} \right.$i.e. $\Lambda _{m\left( {N{H_4}OH} \right)}^0$$\left. {} \right]$ is equal to

$\Lambda _{m\left( {N{H_4}OH} \right)}^0 + \Lambda _{m\left( {NaCl} \right)}^0 - \Lambda _{m\left( {NaOH} \right)}^0$

$\Lambda _{m\left( {NaOH} \right)}^0 + \Lambda _{m\left( {NaCl} \right)}^0 - \Lambda _{m\left( {N{H_4}Cl} \right)}^0$

$\Lambda _{m\left( {N{H_4}OH} \right)}^0 + \Lambda _{m\left( {N{H_4}Cl} \right)}^0 - \Lambda _{m\left( {HCl} \right)}^0$

$\Lambda _{m\left( {N{H_4}Cl} \right)}^0 + \Lambda _{m\left( {NaOH} \right)}^0 - \Lambda _{m\left( {NaCl} \right)}^0$

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