If n = 6, the correct sequence for filling of electrons will be

Question

$ns \to \left( {n - 2} \right)f \to \left( {n - 1} \right)d \to np$

$ns \to \left( {n - 1} \right)d \to \left( {n - 2} \right)f \to np$

$ns \to \left( {n - 2} \right)f \to np \to \left( {n - 1} \right)d$

$ns \to np\left( {n - 1} \right)d \to \left( {n - 2} \right)f$

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