A particle of mass M, starting from rest, undergoes uniform acceleration. If the speed acquired in time T is V, the power delivered to the particle is

Question

${{M{V^2}} \over T}$

${1 \over 2}{{M{V^2}} \over {{T^2}}}$

${{M{V^2}} \over {{T^2}}}$

${1 \over 2}{{M{V^2}} \over T}$

Solution

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