The number of atoms in 0.1 mol of a triatomic gas is (NA = 6.02 $ \times $ 1023 mol$-$1)

Question

The number of atoms in 0.1 mol of a triatomic gas is (N_A = 6.02 $ \times $ 10²³ mol^$-$1)

6.026 $ \times $ 10²²

1.806 $ \times $ 10²³

3.600 $ \times $ 10²³

1.800 $ \times $ 10²²

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