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Question
For the reaction, N2 + 3H2 $ \to $ 2NH3, if
${{d\left[ {N{H_3}} \right]} \over {dt}}$ = 2 $ \times $ 10$-$4 mol L$-$1 s$-$1,
the value of ${{ - d\left[ {{H_2}} \right]} \over {dt}}$ would be
4 $ \times $ 10$-$4 mol L$-$1 s$-$1
6 $ \times $ 10$-$4 mol L$-$1 s$-$1
1 $ \times $ 10$-$4 mol L$-$1 s$-$1
3 $ \times $ 10$-$4 mol L$-$1 s$-$1

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