The two ends of a rod of length L and a uniform cross-sectional area A are Kept at two temperatures T1 and T2 (T1 > T2). The rate of heat transfer, ${{dQ} \over {dt}}$ through the rod in a steady state is given by :

Question

The two ends of a rod of length L and a uniform cross-sectional area A are Kept at two temperatures T₁ and T₂ (T₁ > T₂). The rate of heat transfer, ${{dQ} \over {dt}}$ through the rod in a steady state is given by :

${{dQ} \over {dt}} = {{k\left( {{T_1} - {T_2}} \right)} \over {LA}}$

${{dQ} \over {dt}} = kLA({T_1} - {T_2})$

${{dQ} \over {dt}} = {{kA\left( {{T_1} - {T_2}} \right)} \over L}$

${{dQ} \over {dt}} = {{kL\left( {{T_1} - {T_2}} \right)} \over A}$

Solution

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