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Question
A simple pendulum performs simple harmonic motion about x = 0 with an amplitude a and time period T. The speed of the pendulum at x = a/2 will be
${{\pi a} \over T}$
${{3{\pi ^2}a} \over T}$
${{\pi a\sqrt 3 } \over T}$
${{\pi a\sqrt 3 } \over {2T}}$

Solution

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