The mean free path of electrons in a metal is 4 $ \times $ 10$-$8 m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units V/m

Question

The mean free path of electrons in a metal is 4 $ \times $ 10^$-$8 m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units V/m

$5 \times {10^{ - 11}}$

8 $ \times $ 10^$-$11

5 $ \times $ 10⁷

8 $ \times $ 10⁷

Solution

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