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Question
The value of equilibrium constant of the reaction
HI(g) $\rightleftharpoons$ ${1 \over 2}$H2(g) + ${1 \over 2}$I2(g)
is 8.0. The The equilibrium constant of the reaction
H2(g) + I2(g) $\rightleftharpoons$ 2HI(g) will be
16
1/8
1/16
1/64

Solution

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