Consider the reaction : N2(g) + 3H2(g) $ \to $ 2NH3(g) The equality relationship between ${{d\left[ {N{H_3}} \right]} \over {dt}}$ and $ - {{d\left[ {{H_2}} \right]} \over {dt}}$ is

Question

Consider the reaction : N_2(g) + 3H_2(g) $ \to $ 2NH_3(g)

The equality relationship between ${{d\left[ {N{H_3}} \right]} \over {dt}}$ and $ - {{d\left[ {{H_2}} \right]} \over {dt}}$ is

${{d\left[ {N{H_3}} \right]} \over {dt}} = - {{d\left[ {{H_2}} \right]} \over {dt}}$

${{d\left[ {N{H_3}} \right]} \over {dt}} = - {1 \over 3}{{d\left[ {{H_2}} \right]} \over {dt}}$

$ + {{d\left[ {N{H_3}} \right]} \over {dt}} = - {2 \over 3}{{d\left[ {{H_2}} \right]} \over {dt}}$

$ + {{d\left[ {N{H_3}} \right]} \over {dt}} = - {3 \over 2}{{d\left[ {{H_2}} \right]} \over {dt}}$

Solution

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