A body of mass 3 kg is under a constant force which causes a displacement s in metres in it, given by the relation s = ${1 \over 3}$t2, where t is in seconds. Work done by the force in 2 seconds is
${{19} \over 5}J$
${5 \over {19}}J$
${3 \over {8}}J$
${8 \over {3}}J$
Solution
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