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Question
A photosensitive metallic surface has work function, h$\upsilon $0. If photons of energy $2h{\upsilon _0}$ fall on this surface, the electrons come out with a maximum velocity of 4 $ \times $ 106 m/s. When the photon energy is increased to 5 h$\upsilon $0, then maximum velocity of photoelectrons will be
2 $ \times $ 107 m/s
2 $ \times $ 106 m/s
8 $ \times $ 106 m/s
8 $ \times $ 105 m/s

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