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Question
In the reaction ${}_1^2$H + ${}_1^3$H $ \to $ ${}_2^4$He + ${}_0^1$n, if the binding
energies of ${}_1^2$ H, ${}_1^3$H and ${}_2^4$He are respectively a, b and c (in MeV),
then the energy (in MeV) released in this reaction is
a + b + c
a + b $-$ c
c $-$ a $-$ b
c + a $-$ b

Solution

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