The frequency of radiation emitted when the electron falls from n = 4 to n = 1 in hydrogen atom will be (Given ionization energy of H = 2.18 $ \times $ 10$-$18 J atom$-$1 and h = 6.625 $ \times $ 10$-$34 J s)
1.54 $ \times $ 1015 s$-$1
1.03 $ \times $ 1015 s$-$1
3.08 $ \times $ 1015 s$-$1
2.00 $ \times $ 1015 s$-$1
Solution
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