The densities of graphite and diamond at 298 K are 2.25 and 3.31 g cm$-$3, respectively. If the standard free energy difference $\left( {\Delta {G^o}} \right)$ is equal to 1895 J mol$-$1, the pressure at which graphite will be transformed into diamond at 298 K is

Question

The densities of graphite and diamond at 298 K are 2.25 and 3.31 g cm^$-$3, respectively. If the standard free energy difference $\left( {\Delta {G^o}} \right)$ is equal to 1895 J mol^$-$1, the pressure at which graphite will be transformed into diamond at 298 K is

11.14 $ \times $ 10⁸ Pa

11.14 $ \times $ 10⁷ Pa

11.14 $ \times $ 10⁶ Pa

11.14 $ \times $ 10⁵ Pa

Solution

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