The e.m.f. of a Daniell cell at 298 K is E1. When the concentration of ZnSO4 is 1.0 M and that of CuSO4 is 0.01 M, the e.m.f. changed to E2. What is the relationship between E1 and E2?

Question

The e.m.f. of a Daniell cell at 298 K is E₁.

When the concentration of ZnSO₄ is 1.0 M and that of CuSO₄ is 0.01 M, the e.m.f. changed to E₂. What is the relationship between E₁ and E₂?

E₁ > E₂

E₁ < E₂

E₁ = E₂

E₂ = 0 $ \ne $ E₁

Solution

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