A stone is tied to a string of length $l$ and is whirled in a vertical circle with the other end of the string as the centre. At a certain instant of time, the stone is at its lowest position and has a speed u. The magnitude of the change in velocity as it reaches a position where the string is horizontal (g being acceleration due to gravity) is
$\sqrt {2\left( {{\mu ^2} - gl} \right)} $
$\sqrt {{u^2} - gl} $
$u - \sqrt {{u^2} - 2gl} $
$\sqrt {2gl} $
Solution
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