Consider two rods of same length and different specific heats (S1, S2), conductivities (K1, K2) and area of cross-sections (A1, A2) and both having temperatures T1 and T2 at their ends. If rate of loss of heat due to conduction is equal, then

Question

Consider two rods of same length and different specific heats (S₁, S₂), conductivities (K₁, K₂) and area of cross-sections (A₁, A₂) and both having temperatures T₁ and T₂ at their ends. If rate of loss of heat due to conduction is equal, then

K₁A₁ = K₂A₂

${{{K_1}{A_1}} \over {{S_1}}} = {{{K_2}{A_2}} \over {{S_2}}}$

K₂A₁ = K₁A₂

${{{K_2}{A_1}} \over {{S_2}}} = {{{K_1}{A_2}} \over {{S_1}}}$

Solution

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