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Question
Change in enthalpy for reaction,

2H2O2(l) $ \to $ 2H2O(l) + O2(g)

if heat of formation of H2O2(l) and H2O(l) are $-$188 and - 286 kJ/mol respectively, is
$-$ 196 kJ/mol
+ 196 kJ/mol
+948 kJ/mol
$-$ 948 kJ/mol

Solution

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