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Question

meso form

racemic mixture

d-form

$l$-form

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Step-by-Step Explanation Step 1: Recognize the Presence of Chirality The given compound (as shown in the question) has chiral centers. A chiral center is typically a carbon atom bonded to four different groups. When a molecule has these chiral centers and lacks an internal plane of symmetry, it can exist in two non-superimposable mirror image forms called enantiomers. Step 2: Formation of Enantiomers During the synthesis or reaction pathways of such compounds, both possible enantiomers often form in equal proportions if there is no chiral influence (like a chiral catalyst or reagent). This leads to the generation of two enantiomers (the d- and l- forms) in a 1:1 ratio. Step 3: Definition of a Racemic Mixture A racemic mixture is one in which two enantiomers are present in equal amounts. Such a mixture is optically inactive overall because the optical rotation caused by one enantiomer cancels out the optical rotation caused by the other. As a result, there is no net rotation of plane-polarized light. Step 4: Conclusion Since the product is formed as an equal mixture of two enantiomers (mirror images), it is termed a “racemic mixture.” This precisely explains why the correct answer is “racemic mixture.” Solution Reference Image

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