If a ${}_b^aX$ species emits first a position, then two a and two b particles and in the last, one a, is also emitted and gets converts to ${}_d^c$Y species. So correct relation is
c = a $-$ 12, d = b $-$ 5
c = a $-$ 5, d = b $-$ 1
c = a $-$ 6, d = b $-$ 0
c = a $-$ 4, d = b $-$ 2
Solution
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