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Question
Two waves having equation x1 = $a$sin($\omega $t $-$ kx + $\phi $1), x2 = asin($\omega $t $-$kx + $\phi $2). If in the resultant wave the frequency and amplitude remain equal to amplitude of superimposing waves, the phase difference between them is
${\pi \over 6}$
${{2\pi } \over 3}$
${\pi \over 4}$
${\pi \over 3}$

Solution

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