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Question

The rise in boiling point of a solution containing $1.8 \mathrm{~g}$ of glucose in $100 \mathrm{~g}$ of solvent is $0.1^{\circ} \mathrm{C}$. The molal elevation constant of the liquid is

$1 \mathrm{~K} \mathrm{~kg} / \mathrm{mol}$
$2 \mathrm{~K} \mathrm{~kg} / \mathrm{mol}$
$10 \mathrm{~K} \mathrm{~kg} / \mathrm{mol}$
$0.1 \mathrm{~K} \mathrm{~kg} / \mathrm{mol}$

Solution

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