$\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7$ on heating liberates a gas. The same gas will be obtained by

Question

heating $\mathrm{NH}_4 \mathrm{NO}_2$

treating $\mathrm{H}_2 \mathrm{O}_2$ with $\mathrm{NaNO}_2$

treating $\mathrm{Mg}_3 \mathrm{~N}_2$ with $\mathrm{H}_2 \mathrm{O}$

heating $\mathrm{NH}_4 \mathrm{NO}_3$

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