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Question

If $A$ and $B$ are two events such that $P(A)=\frac{1}{2}, P(B)=\frac{1}{2}$ and $P(A \mid B)=\frac{1}{4}$, then $P\left(A^{\prime} \cap B^{\prime}\right)$ is

$\frac{1}{8}$
$\frac{3}{16}$
$\frac{1}{12}$
$\frac{3}{4}$

Solution

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