Let the relation $R$ is defined in $N$ by $a R b$, if $3 a+2 b=27$ then $R$ is

Question

$\{(1,12)(3,9)(5,6)(7,3)\}$

$\left\{\left(0, \frac{27}{2}\right)(1,12)(3,9)(5,6)(7,3)\right\}$

$\{(1,12)(3,9)(5,6)(7,3)(9,0)\}$

$\{(2,1)(9,3)(6,5)(3,7)\}$

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