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Question

If $A=\left[\begin{array}{ll}0 & 1 \\ 0 & 0\end{array}\right]$, then $(a I+b A)^n$ is (where $I$ is the identify matrix of order 2)

$a^2 I+a^{n-1} b \cdot A$
$a^n I+n \cdot a^{n-1} b \cdot A$
$a^n I+n a^n b A$
$a^n I+b^n A$

Solution

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