If $y=\left(1+x^2\right) \tan ^{-1} x-x$, then $\frac{d y}{d x}$ is - DASH

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Question

If $y=\left(1+x^2\right) \tan ^{-1} x-x$, then $\frac{d y}{d x}$ is

$2 x \tan ^{-1} x$

$\frac{\tan ^{-1} x}{x}$

$x^2 \tan ^{-1} x$

$x \tan ^{-1} x$

Solution

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