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Question

If $\int \frac{d x}{(x+2)\left(x^2+1\right)}=a \log \left|1+x^2\right|+b \tan ^{-1} x +\frac{1}{5} \log |x+2|+c,$ then

$a=\frac{-1}{10}, b=\frac{2}{5}$

$a=\frac{1}{10}, b=\frac{2}{5}$

$a=\frac{-1}{10}, b=\frac{-2}{5}$

$a=\frac{1}{10}, b=\frac{-2}{5}$

Solution

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