Your AI-Powered Personal Tutor
Question

The distance of the point whose position vector is $(2 \hat{\mathbf{i}}+\hat{\mathbf{j}}-\hat{\mathbf{k}})$ from the plane $\mathbf{r} \cdot(\hat{\mathbf{i}}-2 \hat{\mathbf{j}}+4 \hat{\mathbf{k}})=4$ is

$\frac{8}{\sqrt{21}}$
$8 \sqrt{21}$
$-\frac{8}{\sqrt{21}}$
$-\frac{8}{21}$

Solution

Please login to view the detailed solution steps...

Go to DASH