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Question

A convex lens of focal length $f$ is placed somewhere in between an object and a screen. The distance between the object and the screen is $x$. If the numerical value of the magnification produced by the lens is $m$, then the focal length of the lens is

$\frac{m x}{(m-1)^2}$
$\frac{(m+1)^2 x}{m}$
$\frac{(m-1)^2 x}{m}$
$\frac{m x}{(m+1)^2}$

Solution

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