A metallic rod breaks when strain produced is $0.2 \%$. The Young's modulus of the material of the $\operatorname{rod} 7 \times 10^9 \mathrm{~N} / \mathrm{m}^2$. The area of crosssection to support a load of $10^4 \mathrm{~N}$ is

Question

$7.1 \times 10^{-6} \mathrm{~m}^2$

$7.1 \times 10^{-4} \mathrm{~m}^2$

$7.1 \times 10^{-2} \mathrm{~m}^2$

$7.1 \times 10^{-8} \mathrm{~m}^2$

Solution

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