Two tiny spheres carrying charges $1.8 \mu \mathrm{C}$ and $2.8 \mu \mathrm{C}$ are located at $40 \mathrm{~cm}$ apart. The potential at the mid - point of the line joining the two charges is

Question

$2.1 \times 10^5 \mathrm{~V}$

$3.6 \times 10^5 \mathrm{~V}$

$1.3 \times 10^4 \mathrm{~V}$

$3.8 \times 10^4 \mathrm{~V}$

Solution

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