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Question

A bob of mass '$m$' is suspended by a light string of length '$L$'. It is imparted a minimum horizontal velocity at the lowest point $A$ such that it just completes half circle reaching the top most position B. The ratio of kinetic energies $\frac{(K . E)_A}{(K . E)_B}$ is :

5 : 1
3 : 2
1 : 5
2 : 5

Solution

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