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Question

The bob of a pendulum was released from a horizontal position. The length of the pendulum is $10 \mathrm{~m}$. If it dissipates $10 \%$ of its initial energy against air resistance, the speed with which the bob arrives at the lowest point is:

[Use, $\mathrm{g}: 10 \mathrm{~ms}^{-2}$]

$5 \sqrt{6} \mathrm{~ms}^{-1}$
$5 \sqrt{5} \mathrm{~ms}^{-1}$
$2 \sqrt{5} \mathrm{~ms}^{-1}$
$6 \sqrt{5} \mathrm{~ms}^{-1}$

Solution

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