If the total energy transferred to a surface in time $\mathrm{t}$ is $6.48 \times 10^5 \mathrm{~J}$, then the magnitude of the total momentum delivered to this surface for complete absorption will be:

Question

$2.16 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}$

$2.46 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}$

$1.58 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}$

$4.32 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}$

Solution

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