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Question

If $\mathrm{V}$ is the gravitational potential due to sphere of uniform density on it's surface, then it's value at the center of sphere will be:-

$\frac{3 \mathrm{~V}}{2}$
$\frac{\mathrm{V}}{2}$
$\frac{4}{3} \mathrm{~V}$
$\mathrm{V}$

Solution

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